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C语言编辑简易计算器

#includeint main() { double num1 = 0; //输入1 double num2 = 0; //输入2 char ch; //操作 double ret = 0; //结果 printf( "输入第一个数:" ); scanf( "%lf", &num1 ); printf( "输入第二个数:" ); scanf( "%lf", &num2 ); printf( "操

#include<stdio.h> void add(int a,int b,int c) { c=a+b; printf("%d+%d = %d",a,b,c); printf("\n"); } void minus(int a,int b,int c) { c=a-b; printf("%d-%d=%d",a,b,c); printf("\n"); } void multiplication(int a,int b,int c) { c=a*b; printf("%d*%d=%d",

原发布者:持剑观风#include#includeintmain(void){intchoice,t=1;printf("**********************计算器*****************************************\n");printf("1.加法运算2.减法运算\n");printf("3.乘法运算4.除法运算\n");printf("5.平方运算6.开方运算\n

我给你写一个简单的计算器程序,你可以看一下.如果需要更多的功能,那么还要更复杂一些.不是一句话可以说明白的.要用到很多函数的调用,和函数的方法. #include "stdio.h"void main(){int a,b,result;char m;printf("请输入需要计算

#includemain(){ char op; float result,data1,data2; float OP(float x,float y,char t); printf("input op(+,-,*,/):\n",op); scanf("%c",&op); printf("input data1:\n",data1); scanf("%f",&data1); pr

double a,b;char c;scanf("%lf%c%lf",&a,&c,&b);switch(c){case '+':printf("%g%c%g=%g",a,c,b,a+b);break; case '-':printf("%g%c%g=%g",a,c,b,a-b);break; case '*':printf("%g%c%g=%g",a,c,b,a*b);break; case '/':b?printf("%g%c%g=%g",a,c,b,a/b):puts("error");break; default:printf("error");break;}

#include<stdio.h>#include<conio.h>#include<windows.h>void ErrorInfo()//出错提示{printf("The operator Must be \"+,-,*,/\"\n");}int judgeNum(float num)//判断是否为整数{if(num-(int)num==0)return 1;elsereturn 0;}int IsOperator(char ch)//判断

#include <stdio.h>#include <stdlib.h> int main() { float num1, num2; char operate; printf("Please input operation:"); scanf("%f %c %f", &num1,&operate, &num2); switch (operate) { case '+': printf("%f%c%f=%f\n",num1,operate,num2,num1+

#include int main() { float data1, data2; char op; while (3 == scanf("%f%c%f", &data1, &op, &data2) ) { float result; printf("%.6lf%c%.6lf=", data1, op, data2); switch (op) { case '+': result = data1 + data2; break; case '-': result = data1 - data2;

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