www.ylrr.net > 不等式0小于等于x 的平方减2X 减3小于5的解集, 求学霸解答

不等式0小于等于x 的平方减2X 减3小于5的解集, 求学霸解答

-X-2X+3≤0X+2X-3≥0X+3X-1≥0X≤-3 X≥1

x-2x-3(x-3)(x+1)x-3所以,x-30 即-1

x^2-2x-3≤0(x-3)(x+1)≤0-1≤x≤3

x-2x-3<0(x-3)(x+1)<0原不等式的解集为{x|-1<x<3}

x-2x-3≥0 (x+1)(x-3)≥0 解得x= -1或x=3 所以解集为{x|x≥3或x≤-1}

先转换成(x-3)(x+1)>0,令(x-3)(x+1)=0,解得x=3,x=-1,再由口诀大于0取两边,小于0取中间,得x>3或x<-1

x^2 - 2x - 3 < 0 ==> (x -3)(x +1) < 0 ==> -1 < x < 3 x^2 + 4x - 5 < 0 ==> (x +5)(x - 1) < 0 ==> -5 < x < 1 AUB = {x| -5 < x < 3}求采纳

解,x-2x-3 (x+1)(x-3)所以(-1,3)

X-2X-5 >2X (X+1)(X-5) >0 (1)X+1 >0 X >-1, X-5 >0 X >5 (2)X+1

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